1. The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 Å apart is,\(\left(m_e ~ 9 ×10^{−31} kg, e =1.6 ×10^{−19} C\right)\) take, \(\left(\frac{1}{4\pi \epsilon _0} = 9 x 10^9 Nm^2C^{-2}\right)\)